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skrubbe Land mørk d omregn stofmængdekoncentrationen til g l omvendt markedsføring Due

$\begin{array}{llllll} a)\\& \begin{array}{llllll} \left [ Fe(NO_3)_3\cdot9H_2O \right ]\;_{\textit{(s)}}\;\longrightarrow \;Fe^{3+}\;_{\textit{(aq)}}\:+\;3\;N{O_3}^-\;_{\textit{(aq)}}\;+\;9\,H_2O\;_{\textit{(l)}} \end{array}\\\\\\ b)\\& \begin{array}{llllll} M( Fe(NO_3)_3\cdot 9H_2O)=\left (241.86+9\cdot 18.015 \right )\;\frac{g}{mol}=403.995\;\frac{g}{mol}\\\\ n( Fe(NO_3)_3\cdot 9H_2O)=n(Fe(NO_3)_3)=\frac{2.85\;g}{403.995\;\frac{g}{mol}}=0.007055\;mol\\\\ \left [ Fe(NO_3)_3 \right ]=\frac{0.007055\;mol}{0.250\;L}=0.028218\;M \end{array}\\\\\\ c)\\& \begin{array}{llllll} \left [ Fe^{3+} \right ]=\left [ Fe(NO_3)_3 \right ]&=&0.028218\;M\\\\ \left [ N{O_3}^- \right ]=3\cdot \left [ Fe(NO_3)_3 \right ]&=&0.084655\;M \end{array}\\\\\\ d)\\& \begin{array}{llr} \left [ Fe^{3+} \right ]_{\textup{fort}}=\frac{1}{3}\cdot \left (0.028218\;M \right )&=&9.406\;mM\\\\ \left [ N{O_3}^- \right ]_{\textup{fort}}=\frac{1}{3}\cdot \left ( 0.084655\;M \right )&=&28.218\;mM \end{array} \end{array}$